[3(x-1)=15

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Solution for [3(x-1)=15 equation: 



3(x-1)=15

We move all terms to the left:

3(x-1)-(15)=0

We multiply parentheses

3x-3-15=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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